(a)
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
(d) constant is -45
On a long hike Lucy drank 6 pints of water, which is equal to 3 quarts.
<h3>What is quarts?</h3>
An English measurement of volume equal to one-quarter gallon is the quart. There are now three different types of quarts in use: the liquid quart, dry quart, and imperial quart of the British imperial system. One liter is roughly equivalent to each. It is divided into four cups or two pints (in the US). The precise dimensions of the quart have historically changed in line with shifting values of gallons over time and in relation to various commodities.
A measure of liquid capacity that is equal to two pints or a quarter of a gallon, or roughly 0.94 liter in the US and 1.13 liter in the UK.
Since, 1 quart = 2 pints
Therefore by unitary method we can say,
2pint= 1 quart
6pint= 3quarts
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4/3
explanation : just write it in fraction form
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
