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kari74 [83]
3 years ago
7

PLEASE HELP!!! GEOMETRY please

Mathematics
1 answer:
Cloud [144]3 years ago
4 0
Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85

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What is the sum of all values of m that satisfy 2m (squared) -16m+8=0?
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<h2>Steps:</h2>

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

2m^2-16m=-8

Next, divide both sides by 2:

m^2-8m=-4

Next, we want to make the left side of the equation a perfect square. To find the constant of this perfect square, divide the m coefficient by 2, then square the quotient. In this case:

-8 ÷ 2 = -4, (-4)² = 16

Add 16 to both sides of the equation:

m^2-8m+16=12

Next, factor the left side:

(m-4)^2=12

Next, square root both sides of the equation:

m-4=\pm \sqrt{12}

Next, add 4 to both sides of the equation:

m=4\pm \sqrt{12}

Now, while this is your answer, you can further simplify the radical using the product rule of radicals:

  • Product rule of radicals: √ab = √a × √b

√12 = √4 × √3 = 2√3.

m=4\pm 2\sqrt{3}

<h2>Answer:</h2>

In exact form, your answer is m=4\pm \sqrt{12}\ \textsf{OR}\ m=4\pm 2\sqrt{3}

In approximate form, your answers are (rounded to the hundreths) m=7.46, 0.54

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