Protons positive
Electrons negative
Neutrons neutral
Answer:
a) 0.00070
b) 0.00050
c) 0.00022
d) 0.00016
e) 0.00005
Step-by-step explanation:
Standard error for proportion formula
S.E = √P(1 - P)/n
Where P = proportion
n = number of samples
Assume that the population proportion is 0.46. Compute the standard error of the proportion, σp, for sample sizes of a) 500,000
S.E = √P(1 - P)/n
= √0.46 × 0.54/500000
= √ 4.968 ×10^-7
= 0.0007048404
≈ 0.00070
b) 1,000,000
√P(1 - P)/n
= √0.46 × 0.54/1000000
= 0.0004983974
≈ 0.00050
c) 5,000,000
√P(1 - P)/n
= √0.46 × 0.54/5000000
= √ 4.968 ×10^-8
= 0.0002228901
≈ 0.00022
d) 10,000,000
√P(1 - P)/n
= √0.46 × 0.54/10000000
= √2.484 ×10^-8
= 0.0001576071
≈ 0.00016
e) 100,000,000
√P(1 - P)/n
= √0.46 × 0.54/100000000
= √2.484 × 10^-9
= 0.0000498397
= 0.00005
3.1 % is rounded to the tenths place.
The real percent is 3.06%
Answer:
1.73 or 3+√6/√3+√2
Step-by-step explanation:
1. Simplify the Numerator...3+ the square root of 6 cannot be simplified, so the answer is 5.45
2. Simplify the Denominator.
![17 \sqrt{3} - 2 \sqrt{4} \sqrt{4} \sqrt{2} + 3 \sqrt{9} \sqrt{2} - 4 \sqrt{4} \sqrt{4} \sqrt{3} = 17 \sqrt{3} - 8 \sqrt{2} + 9 \sqrt{2} - 16 \sqrt{3} = \sqrt{3} + \sqrt{2} = 3.15](https://tex.z-dn.net/?f=17%20%5Csqrt%7B3%7D%20%20-%202%20%5Csqrt%7B4%7D%20%20%5Csqrt%7B4%7D%20%20%5Csqrt%7B2%7D%20%20%2B%203%20%5Csqrt%7B9%7D%20%20%5Csqrt%7B2%7D%20%20-%204%20%5Csqrt%7B4%7D%20%20%5Csqrt%7B4%7D%20%20%5Csqrt%7B3%7D%20%20%3D%20%2017%20%5Csqrt%7B3%7D%20%20-%208%20%5Csqrt%7B2%7D%20%20%2B%209%20%5Csqrt%7B2%7D%20%20-%2016%20%5Csqrt%7B3%7D%20%20%3D%20%20%20%20%5Csqrt%7B3%7D%20%20%2B%20%5Csqrt%7B2%7D%20%20%3D%203.15)
3. Divide. 5.45/3.15= 1.73
Answer:
5) The midrange is 19.5ºF
6) The midrange is 67.5º
Explanation:
The problem tell us how to calculate the midrange.
In (5) the minimum and maximum values are given (-6ºF and 45ºF, respectively). Using the formula:
![Midrange=\frac{-6+45}{2}=\frac{39}{2}=19.5ºF](https://tex.z-dn.net/?f=Midrange%3D%5Cfrac%7B-6%2B45%7D%7B2%7D%3D%5Cfrac%7B39%7D%7B2%7D%3D19.5%C2%BAF)
In (6), we need to find the minimum and maximum values from a list of them. We can see that the minimum is 58º and the maximum 77º
Then: