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Bingel [31]
3 years ago
11

All of the points in which quadrant have negative x-coordinates and negative y-coordinates?

Mathematics
2 answers:
pentagon [3]3 years ago
3 0
Quadrant 3 or III
hope this helped

sweet [91]3 years ago
3 0

Answer:

III

Step-by-step explanation:

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The exponential function y= a(b)^x passes through the points (3,25) and (8,10). Which of the following is closest to the value o
Yuki888 [10]

If the exponential function y=ab^x passes through the points (3,25) and (8,10), the value of b is 0.833

The given exponential equation is:

y=ab^x

The function passes through the points (3, 25) and (8, 10)

Substitute x = 3 and y = 25 into the function y=ab^x

25=ab^3............................(1)

Substitute x = 8 and y = 10 into the function y=ab^x

10=ab^8.............................(2)

Divide equation (2) by equation (1)

\frac{10}{25}=\frac{ab^8}{ab^3}  \\\\0.4=b^5\\\\b=0.4^\frac{1}{5} \\\\b=0.4^{0.2}\\\\b=0.833

Therefore, if the exponential function y=ab^x passes through the points (3,25) and (8,10), the value of b is 0.833

Learn more on exponential functions here: brainly.com/question/12940982

6 0
2 years ago
(100 points) Give a step by step explanation on how you solved this problem
Lina20 [59]
Use substitution
Given both y values, you know that they have to be equal

3x + 3 = x - 1
2x + 3 = -1
2x = -4, divide by 2
x = -2
Now plug x value into any of the equation to find y value
y = 3(-2) + 3
y = -6 + 3, y = -3

Solution: x = -2, y = -3
4 0
3 years ago
Read 2 more answers
What is it yalll !??????
diamong [38]

Answer:

I think b

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Help 10 points please
liubo4ka [24]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
The dimensions of a basketball court are shown below. Suppose a player throws the ball from a corner to a teammate standing at t
creativ13 [48]

The 94 ft. by 50 ft dimensions of the court obtained from a similar question posted online, gives;

a. The ordered pair representing the location of the player in the bottom right corner is (47, -25)

b. The distance traveled by the ball obtained using Pythagorean theorem, is approximately 53.2 feet.

<h3>How can Pythagorean theorem be used to find the distance the ball travels?</h3>

The possible dimensions of a rectangular court obtained from a similar question posted online are;

Length of the basketball court = 94ft.

Width of the basketball court = 50 ft.

From the question, we have;

Location of the court center = The origin of a coordinate plane

a. The ordered pair that represent the location of a player in the bottom right corner is found as follows;

Let (x, y) represent the coordinates of the bottom right corner of the court, we have;

Horizontal distance from the center of the court (the origin) to the right boundary of the court, <em>x </em>= (94 ft.)/2 = 47 ft.

Vertical distance from the center to bottom of the court, <em>y </em>= (50 ft.)/2 = 25 ft.

Following the convention of points to the right and above the origin being positive, while points below the origin are negative, we have;

The ordered pair (the coordinates of the player) that represents the location of the player in the bottom right corner is therefore;

  • (x, y) = (47, -25)

b. The distance, <em>d</em>, that the ball travels is given by Pythagorean theorem as follows;

d = √((47 - 0)² + ((-25) - 0)²) = √(2834) ≈ 53.2

  • The ball travels approximately 53.2 feet.

Learn more about Pythagorean theorem here:

brainly.com/question/21332040

#SPJ1

4 0
1 year ago
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