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3 years ago

Work out a) 1 divided by 1/9

Mathematics

2 answers:

melamori03 [73]3 years ago

7 0

Answer:

Step-by-step explanation:

1÷ $\frac{1}{9}$

Convert 1 to a fraction

$\frac{1}{1}$ ÷ $\frac{1}{9}$

Using the KFC rule (or some equivalent)

KEEP the first fraction

FLIP the sign

CHANGE the second fraction

$\frac{1}{1}$ × $\frac{9}{1}$ = $\frac{9}{1}$ = 9

sattari [20]3 years ago

6 0

Answer:

Step-by-step explanation:

To divide a fraction, you turn it into a multiplication problem by reciprocating the fraction.

Reciprocating means making the numerator the denominator and the denominator, the numerator. For instance, 2÷3/4 becomes 2×4/3

1÷1/9=1/1 × 9/1=9

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Step-by-step explanation:

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3 years ago

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3 years ago

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each point

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

$-1\leq \frac{4}{3}(0)+5$

$-1\leq5$ ----> is true

Inequality B

$-1\geq -\frac{5}{2}(0)+5$

$-1\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

$3\leq5$ ----> is true

Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

$-6\leq-3$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

$-6\geq 20$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

$-6\leq \frac{4}{3}(12)+5$

$-6\leq21$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(12)+5$

$-6\geq -25$ ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0

3 years ago