All categories

2 years ago

Work out a) 1 divided by 1/9

Mathematics

2 answers:

melamori03 [73]2 years ago

7 0

Answer:

Step-by-step explanation:

1÷ $\frac{1}{9}$

Convert 1 to a fraction

$\frac{1}{1}$ ÷ $\frac{1}{9}$

Using the KFC rule (or some equivalent)

KEEP the first fraction

FLIP the sign

CHANGE the second fraction

$\frac{1}{1}$ × $\frac{9}{1}$ = $\frac{9}{1}$ = 9

sattari [20]2 years ago

6 0

Answer:

Step-by-step explanation:

To divide a fraction, you turn it into a multiplication problem by reciprocating the fraction.

Reciprocating means making the numerator the denominator and the denominator, the numerator. For instance, 2÷3/4 becomes 2×4/3

1÷1/9=1/1 × 9/1=9

You might be interested in

A hummingbird can make up to 150 flaps in 4 seconds. How long will it take for it to flap its wings 1000 times?

andreev551 [17]

1000/150 = 6 2/3 * 4 = 26 2/3 seconds

6 0

3 years ago

11. Write 343 with an exponent by using<br> 7 as the base.

dimulka [17.4K]

Answer:

343 can be written as

$7 {}^{3}$

Step-by-step explanation:

since we know,

343 = 7 × 7 × 7

so, we can write 343 as cube of 7

hence,

$343 = 7 {}^{3}$

5 0

2 years ago

A baseball coach order hats for his team. Each hat cost $10. The shipping charger is $6. The total cost of the order must be les

NeTakaya

The answer should be:

10h + 6 < 125

3 0

3 years ago

Read 2 more answers

What is the volume of the cone?

mr_godi [17]

1/3 (3.14) (2*2) (4)

8 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago