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Molodets [167]
3 years ago
14

David was in need for some money so he decided to clean out the water fountain at the mall he found 20 nickels and quarters. The

collection of nickels and quarters Totaled to 2.6 how many quarters did David find
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

David find <u>8</u> quarters.

Step-by-step explanation:

Given:

David was in need for some money so he decided to clean out the water fountain at the mall he found 20 nickels and quarters.

The collection of nickels and quarters totaled to 2.6.

Now, to find the quarters David find.

Let the number of nickels be x

And the number of quarters be y

Thus, the number of nickels and quarters he found:

x+y=20.

⇒ x=20-y.........( 1 )

The totaled of nickels and quarters:

0.05x+0.25y=2.6

(As 1 nickel=$0.05 and 1 quarter=$0.25)

Now, putting the equation ( 1 ) in the place of x we get:

0.05(20-y)+0.25y=2.6

⇒ 1-0.05y+0.25y=2.6

⇒ 1+0.20y=2.6

<em>Subtracting both sides by 1 we get:</em>

⇒ 0.20y=1.6

<em>Dividing both sides by 0.20 we get:</em>

⇒ y = 8.

So, the quarters = 8.

Therefore, David find 8 quarters.

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BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

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