-6p^3(3p^2 +5p -1) = -18p^5 -30p^4 +6p^3
so this is the right answer sure
Hello! And thank you for your question!
First add 5/3 to both sides:
2x = 7 + 5/3
Then simplify 7 + 5/3:
2x = 26/3
Then divide both sides by 2:
x = 26/3 over 2
After that simplify 26/3/2:
x = 26 over 3 x 2
Simplify 3 x 2:
x = 26/6
Simplify:
x = 13/3 or 4 1/3
Final Answer:
x = 13/3 or 4 1/3
This conversion<span> of </span>720 seconds<span> to </span>hours<span> has been calculated by multiplying </span>720 seconds<span> by 0.0002 and the result is 0.2 </span>hours<span>.</span>
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
