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aev [14]
3 years ago
15

Which statement explains how the lines 2x + y = 4 and y = one halfx + 4 are related?

Mathematics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

They are perpendicular

Step-by-step explanation:

To solve this problem .

we will convert the equations in slope intercept form.

Slope intercept  form of equation is y = mx+c

where m is slope of line and c is y intercept.

________________________________

equation 1 is

2x+y = 4

=> y =4 - 2x or y = -2x + 4

comparing it with y = mx + c

m = -2  , c = 4

_________________________________________

equation 2 is y = one halfx + 4 ( one half is same as 1/2)

so equation is

y = x/2 +4

comparing it with y = mx + c

m = 1/2  , c = 4

_________________________________________

Now lets evaluate options

They are parallel.  wrong option

For lines to be parallel slope should be same.

But here slope are different -2 and 1/2 .

Thus lines are not parallel.

__________________________________________

They are perpendicular.  correct option

For lines to be perpendicular, product of slope should be equal to -1.

-2*1/2 = -1

we can see that product of slope should be equal to -1 .

Thus lines are  perpendicular

______________________________________

They are the same line.  wrong option

For lines to be same both slope and y intercept should  be same.

Y intercept is same but the slopes are different -2 and 1/2  .

Thus lines are not  the same line.

__________________________________________

They are not related.       wrong option

As we have found that the lines are perpendicular .

So this option is intuitively wrong

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Which transformations of quadrilateral PQRS would result in the image of the quadrilateral being located only in the first quadr
masha68 [24]

Answer:

E

Step-by-step explanation:

<em>The first quadrant is the top-right one</em>

<em>If a point is in the first quadrant, the x- and y-values of the point are both positive</em>

<em />

Let's go through the one by one.

A) Translating the quadrilateral right 4 units will make the new S to be (-3+4, -7)=(1, -7), which is not in the first quadrant.

B) Reflection the quadrilateral across x=4 will not change the y-value of any points. So, the new S will stay below the x-axis, and thus will never be in the first quadrant, because it will always have a negative y-value.

C) This one is tricky. We can prove(the proof is just taking cases of which quadrant) that if a point is in the second or fourth quadrant, it's reflection across the line y=-x will always be in the same quadrant it started in(i.e. reflect a point in the second quadrant, you get a point in the second quadrant). We know that P is in the second quadrant, so the new P will also be in the second quadrant. Therefore, the new quadrilateral will not be entirely in the first quadrant.

D) We intuitively(and can prove) that because R is right underneath Q, the new R will be directly to the left of Q, with the same distance as Q to original R. So, the new R will be (-10, 12) using above method. This point is not in the first quadrant.

E) We know intuitively(and can prove) that a reflection across the line x=3 will make the entire quadrilateral in the first and fourth quadrant. However, When we translate up, the new S, the lowest point on the quadrilateral, will be above the x-axis, making all the points in the first quadrant! Therefore, E works.

F) When we reflect across the x-axis, any points in the second quadrant go to the third quadrant. So, the new P will be in the third quadrant. However, when we translate up 13 units, the new P will go to the second quadrant. It will never cross the y-axis, and will always have a negative x-coordinate. Therefore, P will not be in the first quadrant.

Summing up the cases that work, we get that \boxed{E} is the only answer.

7 0
3 years ago
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