Bonjour, (as you write in roumain)
Soient a et b les 2 nombres
(a+b)/2=200==>a+b=400
8/a=4.5/b==>16b=9a
a+9a/16=400
==> 25a/16=400
==>a=400*16/25
==>a=256
et b= 9*256/16; b=144
Step-by-step explanation:
Given that,
Two equations,
3x + 11 = 11 .....(1)
And
3(x - 3) = 45
or
3x-9=45 ....(2)
Subtract 11 on both sides of equation (1).
3x + 11-11 = 11-11
3x=0
x = 0
Add 9 to both sides of equation (2)
3x-9+9=45+9
3x = 54
x = 18
Hence, the solution of equation (1) is x=0 and form equation (2) x = 18.
Length is 95 yards.
The perimeter of a rectangle is the sum of four sides. The four sides are either its length or width.
A rectangle has four sides where its angles are all right angles and its opposite sides are congruent or of equal size.
Perimeter = 2length + 2width ==> P = 2L + 2W
354 = 2L + 2(82)
354 = 2L + 164
to get the length. we must transfer all like signs.
2L = 354 - 164
2L = 190
2L / 2 = 190 / 2
L = 95 yards.
Answer:
just post a new one
Step-by-step explanation:
<h3>Given</h3>
A regular polygon with area 500 ft² and apothem 10 ft
Cost of fence is $7.95 per ft
<h3>Find</h3>
Part III The cost of fence around an area scaled to 60 times the size
<h3>Solution</h3>
You don't want to think too much about this, because if you do, you find the regular polygon has 3.087 sides. The closest approximation, an equilateral triangle, will have an area of 519.6 ft² for an apothem of 10 ft.
For similar shapes of scale factor "s", the larger shape will have an area of s² times that of the smaller one. Here, it appears the area scale factor s² is 60, so the linear scale factor is
... s² = 60
... s = √60 ≈ 7.7460
The perimeter fence of the 500 ft² area is presumed to be 100 ft long (twice the area of the polygon divided by the apothem—found in Part I), so the perimeter fence of the industrial farm is ...
... (100 ft)×7.7460 = 774.60 ft
and the cost to construct it is
... ($7.95/ft)×(774.60 ft) ≈ $6158
