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Keith_Richards [23]

3 years ago

9

the dashed triangle is a dilation image of a solid triangle with the center at the organ is the dilation an enlargement or reduc

tion find the scale factor of the dilation

1 answer:

Kruka [31]3 years ago

4 0

The image<span> is inverted. The </span>figure<span> and the </span>image<span> have a common point. The common point is the </span>center<span> of </span>dilation<span>. </span>

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olga nikolaevna [1]

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72

Step-by-step explanation:

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2 years ago

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Witch is taller 5'3" or 62 inches?

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3 years ago

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1.) If I am selling a dozen at $3, how much would each egg cost?

riadik2000 [5.3K]

Answer:

1.$3÷12=0.25

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6 0

3 years ago

denis23 [38]

Answer:

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

Step-by-step explanation:

When an object is moving at a steady speed, we can calculate the time it would take to travel a given distance using the following formula:

$time=\frac{distance}{speed}$ (equation 1)

In this particular, both the given speed and distance are mixed fractions so we'll first convert them into improper fractions to operate more easily:

$speed=10\frac{1}{10} \frac{mi}{h} =\frac{(10*10)+1}{10} \frac{mi}{h}=\frac{101}{10} \frac{mi}{h}$

$distance=4\frac{9}{10}mi=\frac{(4*10)+9}{10}mi=\frac{49}{10}mi$

So, now we can calculate the time using the equation 1:

$time=\frac{distance}{speed}=\frac{\frac{49}{10}mi }{\frac{101}{10} \frac{mi}{h} } =\frac{49*10}{101*10} h$

$time=\frac{49}{101}h=0.49h$

And, if we want the result in minutes:

$time=\frac{49}{101}h*\frac{60min}{1h} =29.11min$

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

5 0

2 years ago

If it took Carlos 30 minutes to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 mi

Ivanshal [37]

Answer:

1) No

2) Yes

Step-by-step explanation:

Given : If it took Carlos 30 minutes to cycle from his house to the library yesterday.

To find : Was the distance that he cycled greater than 6 miles?

Solution :

The relation between speed , distance and time is

$\text{Distance}=\text{Speed}\times \text{Time}$

1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second.

Speed = 16 feet per second

Converting into miles, $s=\frac{16}{5280}$

Time = 30 minute

Converting into seconds, $t=30\times 60$

The distance he covered is

$\text{Distance}=\frac{16}{5280}\times30\times 60$

$\text{Distance}=5.45\text{ miles}$

No, the distance that he cycled is not greater than 6 miles.

2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second.

Speed = 18 feet per second

Converting into miles, $s=\frac{18}{5280}$

Time = 30 minute

Converting into seconds, $t=30\times 60$

The distance he covered is

$\text{Distance}=\frac{18}{5280}\times30\times 60$

$\text{Distance}=6.13\text{ miles}$

Yes, the distance that he cycled is greater than 6 miles.

6 0

3 years ago