Ask question

Ask question

All categories

3 years ago

6

The product of two numbers does not change with the change in the order of the numbers. This is called the ___________ property

of multiplication.

1 answer:

xxMikexx [17]3 years ago

8 0

Answer:

assosiative property

Step-by-step explanation:

hope it helps ,pls mark as brainlist

You might be interested in

(help)Name the intersection of the two planes in the image below.

serg [7]

Answer:

XZ

Step-by-step explanation:

The intersection of the 2 planes is along the line XZ

3 0

3 years ago

Mark is in training for a bicycle race. He needs to ride 50 kilometers a week as part of his training. He rode 18.23 kilometers

marishachu [46]

Answer:

17.83 km

Step-by-step explanation:

7 0

3 years ago

Please help me I really need help I’m gonna give 33 points for this please help

lidiya [134]

Answer:

Step-by-step explanation:

1a) use letter "P" for perimeter

1b) use letter "L" or "x"

1c) Formula: P=4L or P=4x

2) the formula for the perimeter of a square is P=4L or P=4x because to find the perimeter you have to add up all the sides, and for a square, all the sides are equal, so it is P=4L or P=4x.

4 0

3 years ago

Read 2 more answers

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute <em>h</em> in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for <em>d</em>, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

DUE IN A HALF HOUR! HELP QUICK!

Blizzard [7]

Answer:

x<=4, put the closed circle on "4" with the arrow going all the way left

3 0

3 years ago