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alexandr402 [8]
3 years ago
5

Please help will give brainlist

Mathematics
2 answers:
Mrac [35]3 years ago
6 0

Answer:

Equation A is nonlinear and Equation B is linear.

If its wrong please tell me and I'll see what i did wrong. Please and Thank you!

Hope this is helpful!

kramer3 years ago
4 0

Answer:

It would be B, Both are linear because the slope is a normal number like 4&-5)

Step-by-step explanation:

They are both linear because they are straight lines.

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What is the surface area of a cylinder with a diameter of 8 and a height of 18?Express the answer in terms of pi
viktelen [127]

Step-by-step explanation:

diameter: 8

radius: 4

height: 18

A=2\pi rh+2\pi r^2\\A=2\pi(4)(18)+2\pi(4)^2\\A=2\pi(72)+2\pi(16)\\A=144\pi+32\pi\\A=176\pi

4 0
3 years ago
(10) Both red line and blue line trains left the station at 5:00 pm. If both
scoundrel [369]

Answer:

5:40

Step-by-step explanation:

This is a problem involving the least common difference.

If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.

The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.

Red:

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

Blue:

10, 20, 30, 40

You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.

6 0
3 years ago
Check picture, 7th grade work.
mina [271]
The answer is 5 cm for the circumference of the smaller square
6 0
3 years ago
Read 2 more answers
Please help
ioda

Answer:

im 12!! how do you do this

Step-by-step explanation:

3 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
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