9514 1404 393
Answer:
a) 1/2
b) 1/2
Step-by-step explanation:
a) The average rate of change is the slope of the segment whose end points are the ends of the interval. On the interval [2, 8] the average rate of change is ...
m = (f(8) -f(2))/(8 -2) = (4 -1)/6 = 3/6 = 1/2
The average rate of change on the interval [2, 8] is 1/2.
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b) In this context, "slope" and "average rate of change" mean the same thing. A line with the same slope will have a slope of 1/2.
Both the computers will take 18 minutes to do the job together.
The slower computer sends all the company's email in 45 minutes.
The faster computer completes the same job in 30 minutes.
Let's take minutes t to complete the task together.
As they complete one job, we get the following equation:
+
=1
LCM of 45 and 30 is:
45 = 3 x 3 x 5
30 = 2 x 3 x 5
LCM = 2 x 3 x 3 x 5 = 90
Now, solving for t;
⇒
Dividing both sides by 5;

We get t = 18
Hence, it will take both the computers 18 minutes to do the job together.
A company has two large computers. The slower computer can send all the company's emails in 45 minutes. The faster computer can complete the same job in 30 minutes. If both computers are working together, how long will it take them to do the job?
Learn more about work and time here brainly.com/question/13086625
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Answer:
in the set of answers: D (no solution )
Step-by-step explanation:
from the possible answers , there is no correct value of x ( A is wrong, B, and C aswell)
the value for x in this equation is equal to 14, hence there is no solution given in the answers
Answer:
Option A, This means that he plants 3 petunias after working in his garden 6 minutes.
Step-by-step explanation:
<u>Step 1: Figure the relationship</u>
6 is the x value which means he spent 6 minutes in garden.
3 is the y value which means he planted 3 petunias.
Answer: Option A, This means that he plants 3 petunias after working in his garden 6 minutes.
I would love to help! However I'm not sure what I'm supposed to be helping with. I could just be daft, but it isn't clear what you need from me.