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tensa zangetsu [6.8K]
3 years ago
11

How do you use equivalent fractions to compare the fractions in each pair

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
Firstly you need to to reduce to a common denominator by multiplYing the whole fraction. This way you have to multiply 4/5 by 2 (both numerator and denominator). so 4/5 = 8/10. And now you have 8/10 and 9/10. You compare only numerators. This way you have 8/10 <9/10. Same goes for 2/3 and 5/8. Only here you need to multiply both fractions. The common denominator here is 24. So you have to multiply 2/3 by 8 and 5/8 by 3. You now have to compare 16/24 and 15/24. 16/24>15/24.
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When a certain polynomial is divide by binomial x-3, the result is 4x-5+6/x-3. What is the polynomial
Dmitry_Shevchenko [17]
\frac{p(x)}{x-3} = 4x-5 + \frac{6}{x-3}

The polynomial p(x) can be found by multiplying 'x-3' to every term
p(x) = (4x-5)(x-3) + 6

Now distribute and you have your answer.
p(x) = 4x^2 -12x-5x+15 +6 \\  \\ p(x) = 4x^2 -17x+21


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D) center

Step-by-step explanation:

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3 years ago
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4 0
3 years ago
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Given z1 = 2 +StartRoot 3 EndRoot i and z2 = 1 – StartRoot 3 EndRoot i, what is the sum of z1 and z2?
Fofino [41]

Answer:

z1 + z2 = 3

Step-by-step explanation:

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8 0
3 years ago
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Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,
ololo11 [35]

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

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3 years ago
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