Explanation:
Provided <u>2 length sides</u> and <u>one angle</u> also need to find <u>one missing side</u>.
So, use cosine rule:
a² = b² + c² - 2bc cos(A)
<h3><u>Part 1</u></h3>
c² = 9² + 11² - 2(11)(9) cos(57)
c² = 94.16147
c = √94.16147 = 9.70 cm
<h3><u>Part 2</u></h3>
d² = 5² + 7² - 2(5)(7) cos(48)
d² = 27.16
d = √27.16 = 5.21
<h3><u>Part 3</u></h3>
5² = 7² + 9² - 2(7)(9) cos(H)
-126cos(H) = 25 - 49 - 81
cos(H) = -105/-126
cos(H) = 5/6
H = cos⁻¹(5/6) = 33.56°
<h3><u>Part 4</u></h3>
8² = 4² + 7² - 2(4)(7) cos(J)
-56cos(J) = 64 - 16 - 49
cos(J) = -1/-56
J = cos⁻¹(1/56) = 88.98°
Passcode: 3142
By reducing 21/30 you dived 21 and 30 by 3 and you will get 7/10. Is 7/10 larger than 2/3? If we put these fractions in decimal form we will see 7/10 turns into 0.7 and 2/3 turns into 0.667. So the answer is 21/30 is larger than 2/3.
Answer:
12/7 is a improper fraction
Step-by-step explanation:
as a decimal it is 1.71428571429 and as a mixed number it is 1 5/7
Answer:
I would set this up as:
let: lesser number = x
greater number = 2x + 5
Restating the word problem:
lesser number + greater number = 38
x + 2x + 5 = 38
Solving: 3x + 5 = 38
- 5 -5
---------------
3x = 33
--- ---
3 3
x = 11
Substitution for the greater number:
2(11) + 5
22 + 5
27
Volume = 2 x 6 x 1 + 1 x 2 x 2
Volume = 16 cubic feet
Shipping Cost = 20 + 1 x 6 = $26
