In
order to solve for a nth term in an arithmetic sequence, we use the formula
written as:<span>
an = a1 + (n-1)d
where an is the nth term, a1 is the first value
in the sequence, n is the term position and d is the common difference.
First, we need to calculate for d from the given
values above.
<span>a3 = 20.5 and a8 = 13
</span>
an = a1 + (n-1)d
20.5 = a1 + (3-1)d
</span>an = a1 + (n-1)d
13 = a1 + (8-1)d
<span>
a1 = 23.5
d = -1.5
The 11th term is calculated as follows:
a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 =
8.5</span>
Answer:
20 hours hope this helps :)
Step-by-step explanation:
Determine the mode(s) of the data 2, 2, 2,3,5,5, 6, 7, 8, 8, 8, 9, 10.
Genrish500 [490]
To find the mode, put all the numbers in order from least to greatest, then count how many times you see a number. The number you see the most is the mode. In this problem, we have more than one mode, we have two. The number two appears three times and so does number eight. Having two modes is called bimodal, and having more than two modes is called multimodal. So we have a bimodal of two and eight from this data.
H = 3.
FIRST STEP:
<span>Add 1 to both sides to get rid of the -1 on the left side.
4h-1 = 3h+2
</span><span>4h-1 (+1) = 3h+2 (+1)
</span><span>4h = 3h+3
SECOND (FINAL) STEP:
Subtract 3h from both sides to get rid of the 3h on the right side.
</span>4h(-3h) = 3h+3 (-3h)
h = 3
Hope this helps, sorry if it's hard to understand :)
