All categories

4 years ago

What is the angle that is half of its own complement?

1 answer:

4 0

If you have an angle and want to know its complement, you subtract it from 90 degrees. What angle, when subtracted from 90 degrees, gives the same value?

90 - x = x

The supplement of x is the angle that you add to x to make 180 degrees. In other words, 180 - x = the supplement of x.

You might be interested in

the Davis family pays 200,000$ for a new house. they make a down payment that is 1/10 of the price of the house.How much is the

Dafna1 [17]

The down payment would be 20,000.

7 0

3 years ago

Given that △ABC ≅ △DEF , m∠E=3y+20, m∠B= 10 +5y, and m∠A=5y , answer the following:

Vinvika [58]

Answer:

y=5

m<A= 25

m<E= 35

Step-by-step explanation:

since <E equals <B due to CPCTC the equation:

3y+20=10+5y

is the equation

8 0

1 year ago

Hi boys can you help me pls!!!!!!!

goblinko [34]

Answer: OPTION A.

Step-by-step explanation:

Given the following function:

$h(x)=-\frac{1}{4}x^2+\frac{1}{2}x+\frac{1}{2}$

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.

Since it is a Quadratic function its graph is parabola.

So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.

You can find the x-coordinate of the Vertex with this formula:

$x=\frac{-b}{2a}$

In this case:

$a=-\frac{1}{4}\\\\b=\frac{1}{2}$

Then, substituting values, you get:

$x=\frac{-\frac{1}{2}}{(2)(-\frac{1}{4}))}\\\\x=1$

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:

$h(1)=y=-\frac{1}{4}(1)^2+\frac{1}{2}(1)+\frac{1}{2}\\\\y=0.75$

Therefore, you can conclude that:

<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>

7 0

3 years ago

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

3 years ago

What is the factored form of 36x4 – 25?

dalvyx [7]

(6x2 + 5) • (5 - 6x2)

5 0

3 years ago