If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
Answer:
5, 9, 10
Step-by-step explanation:
use trial and error
5+9+10=24
9= square number
5 and 10 are factors of 20
(1,42.75) (5,260.75)
260.75-42.72= 218.03
5-1= 4
218.03/4= <span>54.5075
</span>
260.75=5(<span>54.5075)
</span>260.75= <span>272.5375
</span>-272.5375= -11.7875y=54.5075x-11.7875
y=54.5075(8)-11.7875
y=424.27?
4m - 7n = 10
2m + 2n = 4 - multiply everything by -1.
4m - 7n = 10
-2m - 2n = -4 Add the 2 equations
(4m - 7n = 10)
+(-2m - 2n = -4)
-------------------------
2m - 9 n = 6.
The value of 2m - 9n would be 6.
Use this formula:
$5 = $9 then cross multiply 5x= 0.33 x 9
____ _____ You get 5x = 2.97 pounds
<span>0.33 pounds X pounds</span> Then you solve for X.
Divide both sides by 5.
You get 0.594 pounds. Written as a fraction it becomes 59/100 or simply 6/10.
