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3 years ago

If x=at^3 and y=bt^2 then find dy/dx

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

Dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
dy/dx = 2b/3at

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(3p-10q)-(p-8q) I can’t figure this out !!!

Tatiana [17]

Answer: 2p - 2q

Step-by-step explanation:

(3p-10q)-(p-8q) is simply an algebraic expression.

To solve it, you first open the brackets

i.e 3p - 10q - p + 8q (the minus sign between the brackets have multiplied the next minus sign, so it becomes plus sign)

Now, collect the like terms of i.e common terms

= 3p - 10q - p + 8q

= 3p - p - 10q + 8q

= 2p - 2q

Thus, the final expression is 2p - 2q since it cannot be further simplified.

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3 years ago

The function g is defined as g(x)=5x² – 3. Find g(x+1).

maksim [4K]

Answer:

5x² + 10x + 2

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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Karen has calls has 500 or 900 yards of thick soft wool, she has 200 feet at the strore they have 500 feet of wool. How many bal

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Answer:

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Step-by-step explanation:

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3 years ago

What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

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3 years ago