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Ipatiy [6.2K]
3 years ago
13

If x=at^3 and y=bt^2 then find dy/dx

Mathematics
1 answer:
Molodets [167]3 years ago
8 0
Dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
              dy/dx = 2b/3at
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