5x+5+65+65=
Answer:
x=-27
Step-by-step explanation:
We want to find x right, so everything that does not have x you can move to the other side. 5x=-5-65-65. So that should be your equation so far. Now we know that when there are two negatives it is a negative and you add so -5-65=-70-65=-135. So your equation now should be: 5x=-135. Now we can divide -135 with 5 which gives us... -27! There’s your answer. Hope this was correct!
-3 x + 1 > y
1/2x -1 (less than or equal to) y
See photo
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
Answer:
1 and 4 should be the answer or -4x3y2 and 5x4y
Step-by-step explanation:
Ship fast equation for n packages:
2n+(1)x
where x the weight of the packages
Speedy delivery equation for the number of packages:
3n+(0.50)x
The same price happened when:
2n+(1)x = 3n+(0.50)x
x - 0.5x=3n - 2n
x = n/0.5
x = 2n
when the package weight is 2 pounds