Answer:
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n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Solve for x over the real numbers:18 ° (x - 1) (x - 10 ° x) = 0
Divide both sides by 18 °:(x - 1) (x - 10 ° x) = 0
Split into two equations:x - 1 = 0 or x - 10 ° x = 0
Add 1 to both sides:x = 1 or x - 10 ° x = 0
Collect in terms of x:x = 1 or (1 - 10 °) x = 0
Divide both sides by 1 - 10 °:Answer: x = 1 or x = 0
The exponential function shown in the graph is 3^x, so (1/2)3^x is a shrink of it.
Selection B is appropriate.
