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3 years ago

9

Translation 1 unit right and 2 units down Algebraic Rule: Vector:

1 answer:

love history [14]3 years ago

3 0

Answer:

$\large\boxed{\left}$

Step-by-step explanation:

$\vec{v}=\left\\\\x:\\x0-\text{to the right}\\\\y:\\y0-\text{up}$

$\text{1 unit to the right}\to x=1\\\text{2 units down}\to y=-2\\\\\vec{v}=\left\\$

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A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

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A man sold 50 metres of cloth for Rs.5640 at a profit of 20%.

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I) 80% x 5640 = Rs. 4512
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Answer:

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