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madam [21]
3 years ago
14

Select the correct answer.

Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0
I think the answer would be 8+9
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QUICK QUESTION! PLEASE ANSWER FAST!
mr_godi [17]
A^2 + B^2 = C^2
7^2 + B^2 = 25^2
49 + B^2 = 625
-49 -49
B^2 = 576
Square root both sides
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4 0
3 years ago
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PLZZ HELP ME ITD MEAN THE WORLD
SSSSS [86.1K]

Answer: 33/3

Step-by-step explanation:

I don't know the question is weird but it probably is 33/3

8 0
2 years ago
What is the midpoint of C(5,3 and D(-3,-6)
Nat2105 [25]

Answer:

Step-by-step explanation:

Midpoints of two coordinates is expressed using the formula;

M(X, Y) = (x2+x1/2, y2+y1/2)

Given the coordinates  c(5,3) and d(-3,-6)

x1 = 5, y1 = 3, x2 = -3 and y2 = -6

X = x1+x2/2

X = 5+(-3)/3

X = 5-3/2

X = 2/2

X = 1

Also;

Y = y1+y2/2

Y = 3+(-6)/2

Y = 3-6/2

Y = -3/2

Y = -1.5

6 0
2 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
5 0
3 years ago
Find x such that -1/3 = 7/x
Setler [38]

Answer:

x= -21

Step-by-step explanation:

-1/3=7/x

-1x=21

-1x/-1=21/-1

x= -21

7 0
3 years ago
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