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Setler [38]
3 years ago
13

A singles tennis court is a rectangle 27 feet wide and 78 feet long. Suppose a player at corner A hits the ball to her opponent

in the diagonally opposite corner B. Approximately how far does the ball travel, to the nearest tenth of a foot?
Mathematics
1 answer:
Sav [38]3 years ago
6 0
Basically, you just have to find the length of the rectangle that is 27 x 78 feet.
The equation for the diagonal: 
d = sqrt(l^2+w^2)
l = 27
w = 78
plug them in and solve
d = sqrt ( (27^2) + (78^2) )
d = sqrt ( 729 + 6084 )
d = sqrt ( 6813 )
d <span>≈ 82.5

The ball traveled approximately 82.5 feet from one corner of the rectangular 27 x 78 foot field, diagonally to the other side.

Hope this helps</span>

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ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

3x+y=8 (1)

2x+2y=8 (2)

Let's multiply the first equation by 2 and subtract it to the second equation  

6x-2x+2y-2y=16-8

4x=8  

x=2

Using this value in (1) we can find y.

3(2)+y=8

6+y=8

y=2

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0
3 years ago
4.Find the length of the diagonal of a rectangle having dimensions 16 cm and 12 cm.
nignag [31]

Answer:

20 cm

Step-by-step explanation:

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7 0
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Brrunno [24]

I got this same question on a test, the answer is A.

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3 0
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The 12 girls at Suzie's volleyball camp have decided to wear their camp ID's on loops of string around their necks. If each girl
Alik [6]

Answer:

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Step-by-step explanation:

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Each girl needs = 1/2 yard of strings

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Correct workings:

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3 years ago
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