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Grace [21]
3 years ago
12

A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.542 and t

he coefficient of kinetic friction is 0.294. How much force is needed to begin to move the book and how much force is needed to keep the book moving at a constant velocity
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

Force is needed to begin to move the book and  force needed to keep the book moving at a constant velocity is 10.78 N and 5.85 N.

Explanation:

Given :

Mass of book , M = 2.03 kg.

Coefficient of static friction , \mu_s=0.542 \ .

Coefficient of kinetic friction , \mu_k=0.294\ .

Force, required needed to begin to move the book ,

F=\mu_sN=\mu_s(mg)=0.542\times 2.03\times 9.8=10.78\ N.

Now, We know kinetic friction acts when object is in motion .

Therefore , Force, required o keep the book moving at a constant velocity

F=\mu_kN=\mu_k(mg)=0.294\times 2.03\times 9.8=5.85\ N.

Hence, this is the required solution.

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Two identical cylinders, A and B, contain the same type of gas at the same pressure. Cylinder A has twice as much gas as cylinde
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Answer:

D. TA < TB

Explanation:

From general gas equation, we know that:

PV  = nRT

PV/R = nT

where,

P = pressure of gas

V = volume of gas

R = General gas constant

T = temperature of gas

n = no. of moles of gas

<u>FOR CYLINDER A</u>:

PV/R = (nA)(TA)  _____ eqn (1)

<u>FOR CYLINDER B</u>:

PV/R = (nB)(TB)  _____ eqn (2)

Because, Pressure, Volume are constant for both cylinders.

Comparing eqn (1) and (2)

(nA)(TA) = (nB)(TB)

It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.

nA = 2(nB)

using this in eqn:

2(nB)(TA) = (nB)(TB)

TA = (1/2)(TB)

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Therefore it is clear that the correct option is:

<u>D. TA<TB</u>

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