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user100 [1]
3 years ago
10

What is its speed when it is very far away from the earth?

Physics
1 answer:
LuckyWell [14K]3 years ago
5 0
For this item, I assume that the speed being talked about is that of falling objects. If the object is farther away from the Earth's center, the gravitational energy will have very little effect on it. The speed will therefore be little less. 
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A 2.0-m wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T. What is the magnitude of t
konstantin123 [22]

Answer:

The force experienced  is 0.6 N

Explanation:

Given data

length of wire L= 2 m

current in wire I= 0.6 A

magnetic field B= 0.5

The force experienced can be represented as

F= BIL

F= 0.5*0.6*2\\\F= 0.6 N

7 0
3 years ago
Physics class 9 chapter 8 please tell​ please
natali 33 [55]

Answer:

(a) The motion is uniform

(b)  11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

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s = Δd/Δt............. Equation 1

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7 0
3 years ago
What is the relative energy expense of galloping rather than trotting at 3.5 m/s?
labwork [276]

Answer: Trotting uses only 75 percent of the energy as galloping

Explanation: Trotting is only 300 J/m, whereas galloping is roughly 400 J/m

7 0
3 years ago
A ball is thro.d hit the grouvelocity)?
kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of  height 61.9 m. So that the velocity can be determined by;

      u = \sqrt{\frac{2H}{g} }

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/s^{2}, then;

 u = \sqrt{\frac{2*61.9}{10} }

   = \sqrt{\frac{123.8}{10} }

u  = 3.5185

The velocity of the ball is 3.52 m/s.

3 0
4 years ago
dean is slowing down on his skateboards. he starts at a speed of 5.5 m/s and slows to 1.0 m/s over a time of 3.0 seconds. what i
vekshin1
Use one of the equations of accelerated motion; V2=V1 + at ...see attached

6 0
3 years ago
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