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Nuetrik [128]
3 years ago
12

Question 12 (1 point) Given P(A) 0.34, P(A and B) 0.27, P(A or B) 0.44, what is P(B)? Answer in decimal form. Round to 2 decimal

places as needed. Your Answer: Answer
Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

P(A) = 0.34,    P(A ∩ B) = 0.27   and   P(A ∪ B) = 0.44.

We are to find the probability of event B, P(B) = ?

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.

Thus, the required probability of event B is P(B) = 0.37.

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Step-by-step explanation:

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2nd fraction is negative one-fourth

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\div is converted to \times and the 2nd fraction is reversed i.e.

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Solving above:

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Mrs. Salas drives 115 miles per week to give 9 voice lessons. She deducts the cost of eight gallons of gasoline at $2 per gallon
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