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Leviafan [203]
3 years ago
9

2. Simplify the following problem using the distributive property: 2x+3y+2(x-y)-3x . Show each step in your calculation. Justify

each of your steps using number properties.
Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
Multiply everything in the parenthesis by 2.

2x + 3y + 2x - 2y - 3x

Combine like terms.

x + y

Hope this helps!
Lady_Fox [76]3 years ago
7 0
First use the distributive property to distribute the 2

2x+3y+2x-2y-3x

Next combine like terms (combine the x’s with the x’s, and the y’s with the y’s)

-x+y is your answer
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Change each of the following decimals to a fraction. Reduce your answer to its lowest terms.
cluponka [151]
7/100

3/10

21/125

3/ 2500

7/50

I simplified them for you
8 0
2 years ago
Estimates of the number of cells in the human body vary over an order of magnitude.​ Indeed, the precise number varies from one
Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰;  b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times  \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}

b) No. of cells in 1 L

\text{No. of cells} =  \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}

7 0
3 years ago
Which expression is equivalent to<br> 5^10 x 5^5?<br><br> a.5^2<br> b.5^5<br> c.5^15 <br> d.5^50
Elena L [17]
I would like to say D I believe
8 0
3 years ago
Read 2 more answers
The bids in an online auction are represented by the arithmetic sequence shown below. Write an explicit formula to represent the
zmey [24]

(a) The nth term of the sequence is given by A(n)=195 + (n - 1)10.

(b) The 12th term of the sequence is A(12) = 305.

<h3>What is an arithmetic sequence?</h3>

One arithmetic progression with a common difference of 2 is the sequence 5, 7, 9, 11, 13, 15,...

The term "finite arithmetic progression" or "arithmetic progression" refers to a limited segment of an arithmetic progression.

A mathematical sequence has the following structure: a, a+d, a+2d, a+3d, etc., up to n terms. The initial term is a, the shared distinction is d, and n is the total number of words. Find the AP, the first term, the number of terms, and the common difference for the computation using the arithmetic sequence formulae. To determine the nth term, sum, or common difference of a given arithmetic sequence, many formulae related to arithmetic series are utilized.

A(n)=195+(n-1)10

The given arithmetic sequence is 195, 205, 215, 225,.....

The first term a =195

The common difference d= 205-195

d =215-205

d =225-215

So, d = 10

(a) The nth term is given by

A(n)=a+(n-1)d

A(n)=195+(n-1)10

(b) For n=12, the 12th term is given by

A(12)=195+11(10)

A(12)=305

Therefore, A(n)=195+(n-1)10

And A(12)=305

To know more about the arithmetic sequences, visit:

brainly.com/question/15412619

#SPJ1

8 0
1 year ago
URGENT: Find two functions f(x) and g(x) such that f[g(x)] =x but g[f(x)] does not equal x.
Delvig [45]
I think it does equal x but not really fully sure
4 0
3 years ago
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