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Brums [2.3K]
3 years ago
6

You are solving 5 – 83 = y3. Which equation will you get if you multiply both sides by 3?

Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

15 - 3(8³) = 3y³

Step-by-step explanation:

5 – 8³ = y³

3(5 - 8³) = 3(y³)

15 - 3(8³) = 3y³

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How many times can a 40-gallon barrel be filled from 5 casks, each holding 120 gallons?
Mariulka [41]

Answer:

It can be filled 15 times

Step-by-step explanation:

If 5 casks hold 120 gallons each,

5x120= 600

To find how many times a 40gallon barrel can be filled,

= 600/40

= 15

This means a 40 gallon barrel will be filled 15 times.

6 0
3 years ago
Read 2 more answers
In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. There are 75 total red and yellow flowers. How many re
sweet [91]

Answer: there are 25 red flowers in Sakura's garden.

Step-by-step explanation:

In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. This means that if there are 10 red flowers, there would be 20 yellow flowers. if there are 20 red flowers, there would be 40 yellow flowers. Therefore, the ratio of red flowers to yellow flowers in the garden is

5/10 = 10/20 £= 20/40 = 1/2 = 1:2

Total ratio = 2 + 1 = 3

If there are 75 total red and yellow flowers, then the total number of red flowers are in Sakura's garden would be

1/3 × 75 = 25

8 0
3 years ago
Consider the equation below -2(5x + 8) = 14 + 6x complete the statements below with the process used to achieve steps 1-4
Ad libitum [116K]

Step-by-step explanation:

1. Distribute the -2. multiply-2 with 5x and 8. it will be -10x-16=14+6x. For me, i make small numbers negative or positive than big ones. Add 16 to both sides. it will be -10x=30+6x. Subtract 6x. -10x-6x=-16x. Divide both sides by 16. x=30/16= 1 and 14/16

6 0
2 years ago
The price of an item has been reduced by 95% the original price was $17
cricket20 [7]

Answer:$0.85

Step-by-step explanation:

.95x17= 16.15    17.00-16.15=0.85

5 0
2 years ago
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Express 9/41 as a decimal.
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0.2195 hope this helps

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2 years ago
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