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Veseljchak [2.6K]
3 years ago
8

Which values have exactly three significant figures? Check all that apply.

Mathematics
2 answers:
Nina [5.8K]3 years ago
5 0
Can I have the values to check?
Marat540 [252]3 years ago
5 0

Answer:

<h3>0.0230 grams </h3><h3>0.804 inches </h3><h3>140 feet </h3><h3>509 kilometers</h3>

Step-by-step explanation:

The given choices are

  • 0.0230 grams
  • 0.035 ounces
  • 0.804 inches
  • 3.150 liters
  • 140 feet
  • 509 kilometers

Significant figures refer to digit numbers that actually mean something to the measure. For examaple, 0.0230 grams has three significant figures, because there are three digits that give information of the measure. But, 0.035 ounces doesn't have three significant figures, because only two digits give information.

Having said that, all numbers with three significant figures are

  • 0.0230 grams
  • 0.804 inches
  • 140 feet
  • 509 kilometers

All these number have three significant figures because they have three digits that offer information about the measure.

The number 3.150 liters has 4 significant figures, that's why it's not part of the answer.

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at a sale, dresses were sold for $10 each. if the dresses originally cost $200 each, what percentage of its original price was a
Varvara68 [4.7K]

Answer:

5%

Step-by-step explanation:

10/200 = .05

.05 = 5%

7 0
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How to solve this problem 7/20 =
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3 years ago
Jane’s buying clothes. She can get 5 shirts &amp; 4 sweaters for $229 or she can get 2 shirts &amp; 3 sweaters for $128. How muc
makkiz [27]

Cost of 1 shirt is \$25 and cost of one sweater is \$26

<u>Solution: </u>

Given that  Jane’s buying clothes.

She can get 5 shirts & 4 sweaters for \$229

She can get 2 shirts & 3 sweaters for \$128

Need to determine cost of 1 shirt and 1 sweater.

Let assume cost of 1 shirt = \$x

And assume cost of 1 sweater = \$y

Let us create equations from give conditions

First condition is Cost of 5 shirt + cost of 4 sweater = \$229

\begin{array}{l}{\text { cost of 5 shirts }=5 \times \text { cost of 1 shirt }=5 \times x=5 x} \\\\ {\text { cost of 4 sweater }=4 \times \text { cost of 1 sweater }=4 \times y=4 y}\end{array}

So using first condition equation which we get is as follows

5 x+4 y=229 \rightarrow (1)

Second condition is Cost of 5 shirt + cost of 4 sweater = \$128

\begin{array}{c}{\text { cost of } 2 \text { shirts }=2 \times \text { cost of } 1 \text { shirt }=2 \times x=2 x} \\\\ {\text { cost of } 3 \text { sweater }=3 \times \text { cost of } 1 \text { sweater }=3 \times y=3 y}\end{array}

So using second condition equation which we get is as follows

2 \mathrm{x}+3 \mathrm{y}=128\quad\rightarrow (2)

Now we have two equations to be solved

\begin{array}{l}{5 x+4 y=229 \rightarrow (1)} \\\\ {2 x+3 y=128 \rightarrow (2)}\end{array}

On multiplying equation (1) by 2 and equation (2) by 5 to make coefficients of x equal in both equations, we get

\begin{array}{l}{2 x(5 x+4 y)=2\times 229} \\\\ {10 x+8 y=458 \rightarrow (3)} \\\\ {5 x(2 x+3 y)=5 \times 128} \\\\ {10 x+15 y=640 \rightarrow (4)}\end{array}

On subtracting (3) from (4), we get

\begin{array}{l}{(10 \mathrm{x}-10 \mathrm{x})+(15 \mathrm{y}-8 \mathrm{y})=640-458} \\\\ {\Rightarrow 7 \mathrm{y}=182} \\\\ {\Rightarrow \mathrm{y}=\frac{182}{7}=26}\end{array}

On substituting y = 26 in equation (1) we get

\begin{array}{l}{\Rightarrow 5 \mathrm{x}+(4 \times 26)=229} \\\\ {\Rightarrow 5 \mathrm{x}=229-104} \\\\ {\Rightarrow 5 \mathrm{x}=125} \\\\ {\Rightarrow \mathrm{x}=\frac{125}{5}=25}\end{array}

Cost of 1 shirt = \$x = \$25

Cost of 1 sweater = \$y = \$26  

7 0
3 years ago
PLEASE HELP ME!
Harlamova29_29 [7]

Answer:

  d. 12 cm

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Corresponding sides have the given ratio:

  EG/AC = 3/2 = EG/8 . . . . . . . fill in for AC

  EG = 8(3/2) = 12 . . . cm . . . . . . . multiply by 8

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Fittoniya [83]
A century is 100 years, and a millenium is 1000 years.

A centrury is 100/1000 part of  millenium, or simplifying 1/10 or 0.10 part of millenium (or 10%).
8 0
3 years ago
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