54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF: the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then (a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term. So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹ n, being the rank of any element of this geometric progression
This is because the ratio between the two triangles is 1:2 so the side lengths of the first triangle is half the corresponding side length of the second triangle.
