A right triangle has legs of lengths 9 cm and 12 cm. calculate the length of the hypotenuse?
2 answers:
Let the legs of the triangle be a and b, and the hypotenuse c.
Your first instinct might tell you to use the Pythagorean theorem to go about solving this because
. This works, but it is slow.
The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.
Your first instinct might tell you to use the Pythagorean theorem to go about solving this because
The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.
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In the attached, the light-blue figure A''B''C''D'' shows the reflection of ABCD across the y-axis. It is easy to see that figure A'B'C'D' is a translation of that 5 units downward.
The appropriate choice is the 2nd one ...
... Reflection over the y-axis followed by a translation down by 5 units.
Correct question : the width of a rectangle is half of the length. The area is 25 square meters. What is the perimeter ?
Let the Length of the rectangle be 2x m and width be half of the length that is ( 2x ÷ 2 ) = x m
We know, Area of Rectangle = length × width
Applying formula,
=> 25 = 2x × x
=> 25 = 2x²
=> 12.5 = x²
=> ±√12.5 = x
Dimensions can't be negative, taking positive value,
Therefore,
Breadth = x = √12.5 m
Length = 2x = 2√12.5 m
We know, perimeter of Rectangle = 2( Length + Breadth)
Then,
Perimeter = 2( 2√12.5 + √12.5 ) m
Perimeter = 2( 3√12.5 ) m
Perimeter = 6√12.5 m
Hence, perimeter of the rectangle is 6√12.5 m