Answer: The area of the enclosure is 1,029 square meters
Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.
If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as
(X/4) x 7
For the length of the enclosure, we can determine that as follows;
Length = (28/4) x 7
Length = 7 x 7
Length = 49m
And for the width,
Width = (12/4) x 7
Width = 3 x 7
Width = 21m
Therefore, the area is calculated as,
Area = L x W
Area = 49 x 21
Area = 1029 m²
Answer:
Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.
Step-by-step explanation:
Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Variance is 9.
The standard deviation is the square root of the variance.
So

Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So



has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.
$95.00 minus $9.50 equals $85.50