The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
Answer:
Step-by-step explanation:
a) the equation representing the parabola is expressed as
h = -16t² - 4t + 20
c) to determine the height after 25 seconds, we would substitute 25 for t into the given equation. It becomes
h = -16(25)² - 4(25) + 20
h = - 10000 - 100 + 20
h = - 10080
d) when the coin lands on the ground, the height would be 0. Therefore,
-16t² - 4t + 20 = 0
Dividing both sides of the equation by 4, it becomes
- 4t² - t + 5 = 0
- 4t² - 5t + 4t + 5 = 0
- t(4t + 5) + 1(4t + 5) = 0
- t + 1 = 0 or 4t + 5 = 0
t = 1 or t = - 5/4
Since t cannot be negative, then t = 1 second
There are 650 toothpicks in a regular sized box.
That is the volume of the box = 650 toothpicks
Jumbo box is made by doubling all the dimensions.
We know volume = length * width * height = L*W*H
We double all the dimensions for Jumbo box
L becomes 2L
W become 2W
H becomes 2H
Volume of Jumbo box = 2L * 2W * 2H = 8*L*W*H
Volume of jumbo box = 8 * volume of small box
= 8 * 650= 5200
The Jumbo box holds 5200 toothpicks .
The area is 14 units square. It can be calculated by drawing the vertices.
Answer:
The rock formation is approximately 7 feet tall.
Step-by-step explanation:
<em>We can visualize this situation as a triangle and know that the bottom side is </em><em>10</em><em> and the angle of elevation (the angle created by Mike and the ground, looking to the top of a rock). With this information, we can use tangent to solve.</em>
<em>x = the height of the rock formation</em>
tan(22°) = x/10
10 tan(22°) = x
x = ~4.04 feet
<em>We also have to add the </em><em>3 feet</em><em> to it because it is being measured 3 feet above the floor.</em>
x + 3 = 7.04 feet
