slope is -1
we have a point as (-4,3)
we can use slope intercept form of line
we can plug m=-1
now, we can plug point (-4,3)
x=-4 and y=3 and then we can find b
now, we can plug back
and we get
............Answer
Sammi wanted to create a dot plot based on this tally chart
1 answer:
Complete Question:
Sammi wanted to create a dot plot based on this tally chartin which step, if any, did Sammi make a mistake creating his dot plot? (See attached pictures showing the chart tally and the 3 steps)
A. Sammi made a mistake in Step 1 because his number line did not include all numbers in the data set.
B. Sammi made a mistake in Step 2 because he chose a title without knowing if the table represents the number of hours read per week.
C. Sammi made a mistake in Step 3 because he did not correctly plot each dot above the appropriate place on the number line.
D. Sammi did not make a mistake.
Answer:
B. Sammi made a mistake in Step 2 because he chose a title without knowing if the table represents the number of hours read per week.
Step-by-step Explanation:
Taking a good look at Sammi's tally alongside the 3 steps he took, we can tell if he made any mistake or not.
=> Option A is incorrect because Sammi plotted correctly a number line that included all values in the data set. The values from the tally chart shows 3 to 6 hours.
=> Option B is correct, Sammi made a mistake in step 2 as he fails to state an appropriate title that corresponds with what the dots he wants to plot represents.
=> Option C is incorrect because from the tally chart, we can see that Sammi correctly plotted each dot accordingly above where each supposed to be in the number line.
Therefore, we can conclude that Sammi made a mistake in Step 2. Our answer is B.
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Answer:
The correct options are;
1) ΔBCD is similar to ΔBSR
2) BR/RD = BS/SC
3) (BR)(SC) = (RD)(BS)
Step-by-step explanation:
1) Given that RS is parallel to DC, we have;
∠BDC = ∠BRS (Angles on the same side of transversal)
Similarly;
∠BCD = ∠BSR (Angles on the same side of transversal)
∠CBD = ∠CBD = (Reflexive property)
Therefore;
ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency
2) Whereby ΔBCD ~ ΔBSR, we therefore have;
BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1
1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1
SC/BS = RD/BR
Inverting both sides
BR/RD = BS/SC
3) From BR/RD = BS/SC the above we have by cross multiplication;
BR/RD = BS/SC gives;
BR × SC = RD × BR → (BR)(SC) = (RD)(BR).
