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GalinKa [24]
3 years ago
12

F(n)=6.5n+4.5 find the 5th term of the sequence defined by the given rule

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

37

Step-by-step explanation:

To find the fifth term , we have to take the value of n as 5

So, F(5)= 6.5 (5) +4.5

= 32.5 + 4.5

= 37

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Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

x^3=x\cdot x^2, and x(x^2+2x+1)=x^3+2x^2+x. Subtracting this from the numerator gives a remainder of

(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

8x^2=8\cdot x^2, and 8(x^2+2x+1)=8x^2+16x+8. Subtracting this from the previous remainder gives a new remainder of

(8x^2+12x+39)-(8x^2+16x+8)=-4x+31

-84x is not a multiple of x^2, so we're done. Then

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

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3 years ago
Jose walked 5 miles in 2 hours. What was his walking rate in miles per hour?
balandron [24]
It is 2.5 miles per hour
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3 years ago
Read 2 more answers
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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Stolb23 [73]

Answer:

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Step-by-step explanation:

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What is the inverse of f(x)=e^x
enot [183]

Answer:

f^{-1}(x)=\ln{x}

Step-by-step explanation:

An <em>inverse</em> function is any function that "undoes" another function. If we think of the function f as some kind of machine that takes in a number x as input and produces a number f(x) as an output, when we give inverse function f^{-1} the number f(x) as in input, we get x, our original input, as the output f^{-1}(x)

We need a function that undoes f(x)=e^x, and the natural choice for undoing an exponent is with a logarithm. Here, our base is e, so we'll choose \log_e{x}=\ln{x} as our inverse function. Let's see how that works:

f^{-1}(f(x))=\ln{e^x}

\ln{e^x} is the power we have to raise e to to get e^x, which is x, so

f^{-1}(f(x))=\ln{e^x}=x

And we have our function.

8 0
3 years ago
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