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zepelin [54]
3 years ago
7

In how many ways can a committee of five women and four men be formed from a group of seven women and seven men?

Mathematics
1 answer:
vekshin13 years ago
6 0
Number of combinations of 5 women from 7  = 7C5 =  7*6 / 2 = 21
for men its 7C4  = 7*6*5 / 3*2 =  35

Total number of ways = 21*35  = 735
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648 is the three-digit positive integers have three different digits

According to the statement

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4 0
2 years ago
Root 2+ root 32+ root 64​
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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

root^2 + root^{32} + root^{64}

= o^2 rt^2 + o^2 rt^{32} + o^2 rt^{64}

Answer : \boxed{o^2 rt^2 + o^2 rt^{32} + o^2 rt^{64}}

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

6 0
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otez555 [7]
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Explanation: First you multiple 5 and 2 getting you ten
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Then you add -10 and 4 to get -6
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Finally you factor out the number to and divide both the 4 and -6
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7 0
3 years ago
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