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Svetlanka [38]
3 years ago
13

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −6y2 − 9y = −1

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0
-6y^2 - 9y = -1

y= \dfrac{-9+ \sqrt{9^2-4*-6} }{2*6}, \dfrac{-9-\sqrt{9^2-4*-6}}{2*6}


y=  \dfrac{-9+ \sqrt{105} }{12}, \dfrac{-9- \sqrt{105} }{12}
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A chemical manufacturer wishes to obtain 700 litres of a 24% acid solution by mixing a 40% acid solution with a 15% solution. Ho
vekshin1
00 x 0.24 = a x 0.40 + ( 700 -a ) x 0.15 = 0.40 a - 0.15 a + 105.00 
<span>168.00 = 0.25a + 105.00 </span>
<span>a = 252 </span>
<span>Solution with 40% ....................252 liters........................ans </span>

<span>Solution with 15 % ...................700 - 252= 448 liters.........................ans</span>
4 0
3 years ago
Lucy went to Chik Fil A. She bought a meal that cost $9.27. If the tax rate is 6% how
borishaifa [10]

Answer:

$9.83

Step-by-step explanation:

Tax= 6% of 9.27

=\frac{6}{100}*9.27\\\\=\frac{55.62}{100}\\\\=0.5562

Amount paid by her = 9.27 + 0.5562 = 9.8262 = $9.83

4 0
3 years ago
(x-3y+ 3z=-4<br><br> 2x+3y-z =15<br><br> (4x-3y- z=19<br><br> - What is the solution to the system?
lesya [120]

Answer:

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

x-3y+3z=-4 (I equation)

2x+3y-z=15  (II equation )

4x-3y-z=19  (III equation )

Equation II multiply by 3 then add  with equation I

Then, we get

7x+6y=41 ....(Equation IV)

Subtract equation II from equation III then we get

2x-6y=4  (equation V)

Adding equation IV and equation V then, we get

9x=45

x=5

Substitute x=5 in equation V then, we get

2(5)-6y=4

10-6y=4

6y=10-4=6

y=1

Substitute x=5 and y=1 in equation then, we get

5-3(1)+3z=-4

2+3z=-4

3z=-4-2=-6

z=\frac{-6}{3}=-2

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

7 0
3 years ago
Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta
Irina-Kira [14]

Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

y = f(u) in which u = g(x) is given by the following function.

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

7 0
3 years ago
Slant rhyme is created by —
Archy [21]
B.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
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