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3 years ago

Aurelio can choose between 3 pairs of pants and 4 shirts. How many different outcomes are in the sample space?

Mathematics

1 answer:

kherson [118]3 years ago

8 0

Answer:

Step-by-step explanation:

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Need help with this question please!

nevsk [136]

I would say it is A because if you subtract p, the original price by $2.50, you would get d, the discounted price. Look at B u see that you're adding the discount which doesn't make sense. Looking at C, the discounted price of different prices can't always be the same. And finally, D, the discounted price is greater than the original. Also, if you subtract you would get different discounts.

6 0

3 years ago

As an estimation we are told £3 is €4. Convert £18 to euros.

Yuri [45]

Answer:

€24

Step-by-step explanation:

We can use ratios to solve this.

3:4 = 18:x

Cross multiply: 3x = 18*4

Divide: x = 18*4/3

Simplify: x = 6*4 = 24

5 0

2 years ago

What is the value of the expression StartAbsoluteValue negative 7 EndAbsoluteValue + StartAbsoluteValue negative 4 EndAbsoluteVa

dolphi86 [110]

Answer:

Step-by-step explanation: Because the absoulute value of 8 is 8 then the absoultue value of 7 is 7. Then add them together it equals 15 :)

7 0

3 years ago

Read 2 more answers

20 ounces at $7 17 ounces at x dollars

tangare [24]

Make a proportion:
$\frac{20}{7} = \frac{17}{x}$
Then cross multiply and divide to solve.

20x=119

x=5.95

The answer is $5.95

6 0

3 years ago

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago