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vodomira [7]
3 years ago
8

Select all of the following graphs which represent y as a function of x

Mathematics
2 answers:
Elden [556K]3 years ago
7 0
A, B, D, and E are correct.

What makes these a function and the others not is that for each x value, there is only one y value. For C, for example, there are multiple y values for the x value of -2. The same goes for F.
Vesnalui [34]3 years ago
7 0

Answer:

A,b,d, and e

Step-by-step explanation:

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I need help it is confusing?????
algol [13]

Answer:

1. 7

2. 15

3. 181

Step-by-step explanation:

Just make sure that you make your denominator a whole number

1. 9.8/1.4....,you multiply by 10...which only removes the comma but it keeps the structure of the question

Always remember that what you do to the denominator...you also do to the numerator

: 9.8/1.4 × 10/10 = 98/14 = 7

2. 40.5/2.7....,you multiply by 10

: 40.5/2.7 × 10/10 = 405/27 = 15

3. 3.62/0.02...., you multiply by 100

: 3.62/0.02 × 100/100 = 362/2 = 181

5 0
3 years ago
Tan 3( ) tan 3 lim<br> h<br> xh x<br> ® h
I am Lyosha [343]

Answer:

27

Step-by-step explanation:

know that

h = 3

h × h × h

3 × 3 × 3

= 27

4 0
3 years ago
The stock price of the company was $38. The stock price fell to $12.60. Which is the closest to the percent decrease in this sto
Nonamiya [84]

Answer:

66.8421% decrease

Step-by-step explanation:

6 0
3 years ago
I need help please?!!
Sveta_85 [38]

Answer:

72

Step-by-step explanation:

8 0
3 years ago
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
3 years ago
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