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MaRussiya [10]
3 years ago
5

Algebra=pain, Plz help lol

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

I think it's C. 2x^2-15

Step-by-step explanation:

I'm really sorry if I'm wrong my brain is dieing from writing essays in ela.

was I close

Brut [27]3 years ago
4 0
I think it is B

(2x+1)-(x^2-7)
You have to change the + and - on the second set then simplify
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grin007 [14]

The width of the border will be 0.1648... ft  or  1.9786... inches.

<u><em>Explanation</em></u>

Lets assume, the width of the border is  x ft.

The rectangular garden is 15 ft in length and 7 ft in width. So, the area of the garden =(15*7)ft^2= 105 ft^2

Now, the length of the garden including border =(15+2x) ft and the width of the garden including border =(7+2x) ft

So, the area of the garden including the border = (15+2x)(7+2x) ft^2

Thus the area of the border =[(15+2x)(7+2x)-105] ft^2

Total amount of premixed cement needed is  1 yard³ = 27 ft³

As the depth of the border is 44 inches or (\frac{44}{12})ft or (\frac{11}{3})ft, so....

\frac{11}{3}[(15+2x)(7+2x)-105] = 27\\ \\ 11(105+44x+4x^2 -105)=81\\ \\ 11(4x^2+44x)=81\\ \\ 44x^2+484x-81=0

Using quadratic formula....

x= \frac{-484+/-\sqrt{484^2-4(44)(-81)}}{2(44)}\\ \\ x= \frac{-484+/-\sqrt{234256+14256}}{88}\\ \\ x= \frac{-484+/-\sqrt{248512} }{88}\\ \\ x= 0.1648...

<u>(Negative value ignored)</u>

So, the width of the border =0.1648...ft= (0.1648...*12)inches= 1.9786...inches

5 0
3 years ago
Mr. Cornapple is the fruit &amp; vegetable buyer for a large school district. In a given week, he has a budget of $6,550. Bushel
Nina [5.8K]

Answer:

40x + 30y ≤ 6,550

Step-by-step explanation:

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Total number of corn bushels = y

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40x + 30y ≤ 6,550

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3 years ago
Yesterday, the price of a loaf of bread at five supermarkets was $1.49,$1.64,$1.74,$1.52, and $1.66, but today each supermarket
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$1.66 will be the mean of the bread at the supermarkets
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4 years ago
12+n=49 true or false​
Alex777 [14]

It depends because n is just a variable so it can be any number.

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3 years ago
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A group of friends were working on a student film that had a budget of $700. They
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