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Travka [436]
3 years ago
15

Given that log(7) = 0.8451, find the value of the logarithm: log (1/7000)

Mathematics
2 answers:
Anni [7]3 years ago
4 0
The solution to the problem is as follows:

<span>log(1/7000)

= log1 - log7000

= -log(7*10^3)

= -log7 + log10^3

= -log7 + 3

= 0.8451 + 3
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
ankoles [38]3 years ago
4 0

Answer: Hello there!

Let's use some relations:

log(a*b) = log(a) + log(b)

log(a/b) = log(a) - log(b)

log(1) = 0

log(a^b) = b*log(a)

now, we know that log(7) = 0.8451.

we want to finde log(1/7000)

log(1/7000) = log(1) - log(7000) = 0 - log(7000)

=- log(7*1000)

we can write 1000 as 10^3

=- (log(7) + log(10^3)) = -(0.8451 + 3*log(10))

and log(10) = 1

then we have:

-(0.8451 + 3*log(10)) = -(0.8451 + 3*1) = -3.8451

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3 years ago
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PLEASE HELP THIS IS SERIOUS DUE IN 5 MINS
Blizzard [7]

Answer:

You didn't add a specific time frame so I can you a correct answer.

Explanation:

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5 0
3 years ago
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Mr. and Mrs. Lorenzo want to buy a home valued at $213,500. If they have 18% of this amount saved for a down payment, how much h
romanna [79]
It would be: 213500 * 18/100
213500 * 0.18 = $38430

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5 0
3 years ago
The manufacturer offers a $125 rebate on photocopiers purchases before january 1. what is the nest cost of a $1,475 photocopier
Yuri [45]

Answer:

The net cost of the photocopier before january 1 is <u>$1350.</u>

Step-by-step explanation:

Given:

The manufacturer offers a $125 rebate on photocopiers purchases before january 1.

Now, to find the net cost of $1,475 photocopier before january 1.

Amount of rebate before January 1 = $125.

Cost of photocopier = $1,475.

So, to get the net cost of $1475 photocopier before january 1 we subtract the rebate from it:

\$1475-\$125

=\$1350.

Therefore, the net cost of the photocopier before january 1 is $1350.

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