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3 years ago

Given that log(7) = 0.8451, find the value of the logarithm: log (1/7000)

2 answers:

4 0

The solution to the problem is as follows:

log(1/7000)

= log1 - log7000

= -log(7*10^3)

= -log7 + log10^3

= -log7 + 3

= 0.8451 + 3

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

ankoles [38]3 years ago

4 0

Answer: Hello there!

Let's use some relations:

log(a*b) = log(a) + log(b)

log(a/b) = log(a) - log(b)

log(1) = 0

log(a^b) = b*log(a)

now, we know that log(7) = 0.8451.

we want to finde log(1/7000)

log(1/7000) = log(1) - log(7000) = 0 - log(7000)

=- log(7*1000)

we can write 1000 as 10^3

=- (log(7) + log(10^3)) = -(0.8451 + 3*log(10))

and log(10) = 1

then we have:

-(0.8451 + 3*log(10)) = -(0.8451 + 3*1) = -3.8451

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n, n+1 - two consecutive integers

n(n + 1) = 50 use distributive property

n² + n = 50 subtract 50 from both sides

n² + n - 50 = 0

-----------------------------------------------------

ax² + bx + c =0

if b² - 4ac > 0 then we have two solutions:

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4 years ago

Solve the equation: 3 - 2/9b = 1/3b - 7

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Eighth, divide both sides by 5. / Your problem should look like: $\frac{90}{5}$ = b
Ninth, simplify $\frac{90}{5}$ to 18. / Your problem should look like: 18 = b
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