All categories

3 years ago

If a1 = 6 and an = 3 + 2(an-1), then a2 equals no links

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

6 0

Answer:

Step-by-step explanation:

Given that a1 = 6

an = 3 + 2(an-1),

Substitute n = 2 into the formula

a2 = 3 + 2(a1)

a2 = 3 + 2(6)

a2 = 3+12

a2 = 15

Hence the second term of the sequence is 15

You might be interested in

Lines c and d are parallel lines cut by transversal p. Which much be true by the corresponding angles theorem?

Flura [38]

Hello!
The corresponding angle theorem states that if two parallel lines are cut my a transversal, then the corresponding angles are congruent. Therefore, the correct answer is:
B. ∠2 = ∠6

If this was correct, please give it 5 stars!

4 0

3 years ago

Read 2 more answers

The difference between two numbers is 14. if 1/3 of the larger number is subtracted from the smaller number ,the result equals 1

otez555 [7]

Answer:

Step-by-step explanation:

x-y=14

x-1/3y=1/10

-y=14-x

y=-14+x

take out the factors

x-10/30y=3/30

30x-10y=3

substitute

30x-10(-14+x)=3

30x+140-10x=3-140

20x/20=-137/20

x=-6.85

y=-14+(-6.85)

y=-20.85

7 0

3 years ago

NEED HELP ASAP I WILL RATE 5 STARS

masha68 [24]

Answer:

Step-by-step explanation:

If you plug in 5 1/3 to the equation, the result is 6, meaning that the point lies on the line.

5 0

3 years ago

The vertex form of the equation of a parabola is y = 2(x + 3)2 - 5. What is the standard form of the equation?

svet-max [94.6K]

Hello :
<span>y = 2(x + 3)² - 5
y = 2(x²+6x+9) -5
y = 2x² +12x +13...(answer : </span><span>A) y=2x^2+12x+13 )</span>

7 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago