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Basile [38]
3 years ago
13

A right rectangular prism has a square base and a height of 12 feet. Its volume, V, is 300 cubic feet. What are the lengths of t

he sides of the base?

Mathematics
1 answer:
alexira [117]3 years ago
5 0
Notice, it has a square base, so the base or bottom of the rectangular prism, is a square, that means, length = width = x, length and width both have the same value, let's say "x", check the picture below

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32 randomly picked people were asked if they rented or owned their own home, 8 said they rented. Obtain a point estimate of the
Romashka-Z-Leto [24]
Don’t you just subtract?

32-8=24 home owners!

Hope this helps
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3 years ago
Benson sells vacuum cleaners on a commission he earns $75 for each vacuum cleaners sucks how many vacuum cleaner should he sell
Digiron [165]

Answer: Read below!

Step-by-step explanation:

You would want to start off by dividing 75 by 1,400. That will get you your answer.

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3 years ago
Factor the polynomial<br> 16z2 + 25
den301095 [7]

16z^2 + 25

This polynomial is already in lowest terms.

Answer: Cannot be factored.

This happens with certain polynomials.

3 0
3 years ago
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Determine,in each of the following cases, whether the described system is or not a group. Explain your answers. Determine what i
zheka24 [161]

Answer:

(a) Not a group

(b) Not a group

(c) Abelian group

Step-by-step explanation:

<em>In order for a system <G,*> to be a group, the following must be satisfied </em>

<em> (1) The binary operation is associative, i.e., (a*b)*c = a*(b*c) for all a,b,c in G </em>

<em>(2) There is an identity element, i.e., there is an element e such that a*e = e*a = a for all a in G </em>

<em> (3) For each a in G, there is an inverse, i.e, another element a' in G such that a*a' = a'*a = e (the identity) </em>

<em> </em>

If in addition the operation * is commutative (a*b = b*a for every a,b in G), then the group is said to be Abelian

(a)  

The system <G,*> is not a group since there are no identity.  

To see this, suppose there is an element e such that  

a*e = a

then  

a-e = a which implies e=0

It is easy to see that 0 cannot be an identity.

For example  

2*0 = 2-0 = 2

Whereas

0*2 = 0-2 = -2

So 2*0 is not equal to 0*2

(b)

The system <G,*> is not a group either.

If A is a matrix 2x2 and the determinant of A det(A)=0, then the inverse of A does not exist.

(c)

The table of the operation G is showed in the attachment.

It is evident that this system is isomorphic under the identity map, to the cyclic group

\mathbb{Z}_{5}

the system formed by the subset of Z, {0,1,2,3,4} with the operation of addition module 5, which is an Abelian cyclic group

We conclude that the system <G,*> is Abelian.

Attachment: Table for the operation * in (c)

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3 years ago
Which of the following best describes the graph shown below?
Valentin [98]
A -------------------------------------
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4 years ago
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