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3 years ago

The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?

1 answer:

7 0

<span>An impulse is the change in momentum. Momentum is mass times velocity. Because the mass does not change, a change in velocity is what creates an impulse. (14.0 m/s - 6.0 m/s) = 8.0 m/s. (150 kg)x(8.0 m/s) = 1200 kgm/s.</span>

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Fill in the numbers to find a Sum

Alekssandra [29.7K]

Answer:

The numbers are -15 and 100

$\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}$

Step-by-step explanation:

we have

$\frac{2}{10} +\frac{x}{100} =\frac{5}{y}$

Solve the left side

$\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}$

$\frac{20+x}{100}=\frac{5}{y}$

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

$\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}$

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3 years ago

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Troyanec [42]

Answer:

see explanation

Step-by-step explanation:

Note that the difference between consecutive terms is - 8

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3 years ago

What is 4/10, 6/20, and 10/25 in simplest form?

Dennis_Churaev [7]

4/10 in simplest form is 2/5
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3 years ago

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The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

sammy [17]

Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

8 0

3 years ago