Answer:
8 feet per second.
Step-by-step explanation:
We have been given that a car is driving away from a crosswalk. The formula 
expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.
We will use average change formula to solve our given problem.
Therefore, the the car's average speed over the given interval of time would be 8 feet per second.
Answer:
484.84
Step-by-step explanation:
(80/16.5)x100=484.84
How many distinct products can be formed using two different integers from the given set: {–6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4
zhannawk [14.2K]
Number of distinct products that can be formed is 144
<h3>Permutation</h3>
Since we need to multiply two different integers to be selected from the set which contains a total of 12 integers. This is a permutation problem since we require distinct integers.
Now, for the first integer to be selected for the product, since we have 12 integers, it is to be arranged in 1 way. So, the permutation is ¹²P₁ = 12
For the second integer, we also have 12 integers to choose from to be arranged in 1 way. So, the permutation is ¹²P₁ = 12.
<h3>
Number of distinct products</h3>
So, the number of distinct products that can be formed from these two integers are ¹²P₁ × ¹²P₁ = 12 × 12 = 144
So, the number of distinct products that can be formed is 144
Learn more about permutation here:
brainly.com/question/25925367
Answer:
top right
Step-by-step explanation:
roots of an equation = x-intercepts
Answer:640
Step-by-step explanation:
Since 15 out of every 75 fish are more than 30 cm long, the probability of finding a fish more than 30 cm is P(x > 30) = 15/75 = 1/5.
The probability of finding a fish 30 cm or less is P(x ≤ 30) = 1 - P(x > 30)
= 1 - 1/5
= (5 - 1)/5
= 4/5
Since we have 800 fish and the probability of finding a fish 30 cm or less is P(x ≤ 30) = 4/5, then the number of fish in the population that are 30 cm or less in length are 800 × P(x ≤ 30) = 800 × 4/5
= 160 × 4
= 640
So, 640 fish in the population are 30 cm or less in length
