Answer:
3.89
Step-by-step explanation:
5.42+2.25=7.67
7.67-3.78=3.89
Hope this helps
The correct answer is x=5
Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
= 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
= 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
= 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
= 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
= 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.
Answer:
502 m²
Step-by-step explanation:
We require to find b before calculating the surface area.
The volume (V) of a cuboid is calculated as
V = lbh ( l is length, b is breadth and h is height )
Here V = 510, l = b, b = 10 and h = 3, thus
b × 10 × 3 = 510
30b = 510 ( divide both sides by 30 )
b = 17
--------------------------
The opposite faces of a cuboid are congruent, thus
top/bottom area = 2(17 × 10) = 2 × 170 = 340 m²
front/back area = 2(17 × 3) = 2 × 51 = 102 m²
sides area = 2(10 × 3) = 2 × 30 = 60 m²
Surface area = 340 + 102 + 60 = 502 m²
X=7
7x-2=5x+12
+2. +2
7x=5x+14
-5x -5x
2x=14
÷2 ÷2
x=7
