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3 years ago

Please help me solve this problem.

Mathematics

1 answer:

Tasya [4]3 years ago

6 0

Let

x-------> total peanuts originally from the bag

we know that

1) Phillip took 1/3 of the peanuts from the bag--------> (1/3)*x

remaining=x-(1/3)*x-------> (2/3)*x

2) Joy took 1/4 of the remaining peanuts-------> (1/4)*[(2/3)*x]----> (1/6)*x

remaining= (2/3)*x-(1/6)*x------> (1/2)*x

3) Brett took 1/2 of the remaining peanuts------> (1/2)*(1/2)*x-----> (1/4)*x

remaining= (1/2)*x-(1/4)*x-------> (1/4)*x

4) Preston took 10 peanuts------> 10

(1/4)*x-10=71----> multiply by 4 both sides----> x-40=284----> x=324 peanuts

5) Total originally peanuts from the bag is equal to 324 peanuts

6) Phillip took (1/3)*x-----> (1/3)*324=108 peanuts

7) Joy took (1/6)*x------> (1/6)*324=54 peanuts

8) Brett took (1/4)*x------> (1/4)*324=81 peanuts

9) Preston took 10

check

108+54+81+10=253

remaining=324-253------> remaining=71-------> is correct

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Answer:

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Step-by-step explanation:

The value of the car after t years is given by:

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According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

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V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

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The car will be worth $1000 after 12.7 years.

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Answer:

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Step-by-step explanation:

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Diano4ka-milaya [45]

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