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geniusboy [140]

2 years ago

8

Please help me with this

1 answer:

lesya692 [45]2 years ago

5 0

Xxx plys the 2-5 then subtract the difference from the question.

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Joseph typed a 1200- word essay in 25 minutes.at this rate,determine how many words he can type in 45 minutes.

Deffense [45]

First you divide 1200 by 25 (1200/25) it comes out to 48.
That means the he types at a rate of 48wpm. So then all you have to do is multiply 48 and 45 and you get 2160 words.

4 0

2 years ago

4p + 1 > −7 or 6p + 3 < 33?

aleksandr82 [10.1K]

P>-2 or p < 5 is your answer

4 0

3 years ago

Four sisters bought a present for their father. They received a 10% discount on the original price of the gift. After the discou

Pani-rosa [81]

9 dollars represents 90% of the cost. Divide 9 by 0.90 to get the original price, 10 dollars

8 0

2 years ago

Read 2 more answers

manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin

alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) $nCr q^{r} p^{n-r}$

$nCr = \frac{n!}{(n-r)!r!}$

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = $20C18 * 0.97^{18} * 0.03^{20-18}$

P(X=18) = $20C18 * 0.97^{18} * 0.03^{2}$

P(X=18) = 0.0988

P(X=19) = $20C19 * 0.97^{19} * 0.03^{20-19}$

P(X=19) = $20C19 * 0.97^{19} * 0.03^{1}$

P(X=19) = 0.3364

P(X=20) = $20C20 * 0.97^{20} * 0.03^{20-20}$

P(X=20) = $20C20 * 0.97^{20} * 0.03^{0}$

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0

3 years ago

Which order does it go?

gladu [14]

Subtract 4 from each side
Divide both sides by 5
Take square root of both sides
Add 3 to both sides

4 0

2 years ago