<span>(x – h)</span>2<span> + (y – k)</span>2<span> = r</span><span>2
h is your x value and the opposite of k is your y value. r is the radius
so, in the first equation, your center would be (-4,2) and the radius would be 5 because you take the square root of r
So plot (-4,2) and count 5 units left, right, up, and down from that point.
Do the same thing for the second circle. The center is (2,-1) and the radius is 5.6 units
The other graphs are pretty much the same way.
For number 7, plot the center and the other set of coordinates. Count the distance between the center and that point and that is your radius
For number 6, plot the center, and to get the radius, take half of the diameter.
For the last one you have to use the distance formula</span>
Step-by-step explanation:
Since x=35 x = 3 5 is a vertical line, the slope is undefined.
Answer:
Step-by-step explanation:
Hello!
To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:
Sample 1: Compressed soil
X₁: penetrability of a plot with compressed soil.
n₁= 20 plots
X[bar]₁= 2.90
S₁= 0.14
Sample 2: Intermediate soil
X₂: penetrability of a plot with intermediate soil.
n₂= 20 (with outlier) n₂= 19 plots (without outlier)
X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)
S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)
Outlier: 4.26
Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:
Parámeter of interest: μ₁-μ₂
Interval:
[(X[bar]₁-X[bar]₂)±
*Sa
]


[(2.90-2.29)±2.715*0.20
]
[0.436; 0.784]
I hope this helps!